{"componentChunkName":"component---src-templates-blog-post-js","path":"/Problem-Solving/2019-12-30-8958번-OX퀴즈/","result":{"data":{"site":{"siteMetadata":{"title":"Hun's Footsteps 🥷","author":"전여훈","siteUrl":"https://jeonyeohun.netlify.app","comment":{"disqusShortName":"","utterances":"jeonyeohun/jeonyeohun.github.io"},"sponsor":{"buyMeACoffeeId":"jeonyeohun"}}},"markdownRemark":{"id":"9c5c3e40-715e-5235-b031-3f21caf0c4c5","excerpt":"8958번: OX퀴즈 접근 방법: 연속된 갯수를 세는 변수하나를 만들어서 그 변수의 값과 O가 나올 때마다 1을 곱해서 점수를 계속 누적시키면서 더한다. 통과 코드:","html":"<h3 id=\"8958번-ox퀴즈\" style=\"position:relative;\"><a href=\"#8958%EB%B2%88-ox%ED%80%B4%EC%A6%88\" aria-label=\"8958번 ox퀴즈 permalink\" class=\"anchor before\"><svg aria-hidden=\"true\" focusable=\"false\" height=\"16\" version=\"1.1\" viewBox=\"0 0 16 16\" width=\"16\"><path fill-rule=\"evenodd\" d=\"M4 9h1v1H4c-1.5 0-3-1.69-3-3.5S2.55 3 4 3h4c1.45 0 3 1.69 3 3.5 0 1.41-.91 2.72-2 3.25V8.59c.58-.45 1-1.27 1-2.09C10 5.22 8.98 4 8 4H4c-.98 0-2 1.22-2 2.5S3 9 4 9zm9-3h-1v1h1c1 0 2 1.22 2 2.5S13.98 12 13 12H9c-.98 0-2-1.22-2-2.5 0-.83.42-1.64 1-2.09V6.25c-1.09.53-2 1.84-2 3.25C6 11.31 7.55 13 9 13h4c1.45 0 3-1.69 3-3.5S14.5 6 13 6z\"></path></svg></a><a href=\"https://www.acmicpc.net/problem/8958\">8958번: OX퀴즈</a></h3>\n<div class=\"gatsby-highlight\" data-language=\"text\"><pre class=\"language-text\"><code class=\"language-text\">&quot;OOXXOXXOOO&quot;와 같은 OX퀴즈의 결과가 있다. O는 문제를 맞은 것이고, X는 문제를 틀린 것이다. 문제를 맞은 경우 그 문제의 점수는 그 문제까지 연속된 O의 개수가 된다. 예를 들어, 10번 문제의 점수는 3이 된다. &quot;OOXXOXXOOO&quot;의 점수는 1+2+0+0+1+0+0+1+2+3 = 10점이다. OX퀴즈의 결과가 주어졌을 때, 점수를 구하는 프로그램을 작성하시오.</code></pre></div>\n<h3 id=\"접근-방법\" style=\"position:relative;\"><a href=\"#%EC%A0%91%EA%B7%BC-%EB%B0%A9%EB%B2%95\" aria-label=\"접근 방법 permalink\" class=\"anchor before\"><svg aria-hidden=\"true\" focusable=\"false\" height=\"16\" version=\"1.1\" viewBox=\"0 0 16 16\" width=\"16\"><path fill-rule=\"evenodd\" d=\"M4 9h1v1H4c-1.5 0-3-1.69-3-3.5S2.55 3 4 3h4c1.45 0 3 1.69 3 3.5 0 1.41-.91 2.72-2 3.25V8.59c.58-.45 1-1.27 1-2.09C10 5.22 8.98 4 8 4H4c-.98 0-2 1.22-2 2.5S3 9 4 9zm9-3h-1v1h1c1 0 2 1.22 2 2.5S13.98 12 13 12H9c-.98 0-2-1.22-2-2.5 0-.83.42-1.64 1-2.09V6.25c-1.09.53-2 1.84-2 3.25C6 11.31 7.55 13 9 13h4c1.45 0 3-1.69 3-3.5S14.5 6 13 6z\"></path></svg></a>접근 방법:</h3>\n<p>연속된 갯수를 세는 변수하나를 만들어서 그 변수의 값과 O가 나올 때마다 1을 곱해서 점수를 계속 누적시키면서 더한다.</p>\n<h3 id=\"통과-코드\" style=\"position:relative;\"><a href=\"#%ED%86%B5%EA%B3%BC-%EC%BD%94%EB%93%9C\" aria-label=\"통과 코드 permalink\" class=\"anchor before\"><svg aria-hidden=\"true\" focusable=\"false\" height=\"16\" version=\"1.1\" viewBox=\"0 0 16 16\" width=\"16\"><path fill-rule=\"evenodd\" d=\"M4 9h1v1H4c-1.5 0-3-1.69-3-3.5S2.55 3 4 3h4c1.45 0 3 1.69 3 3.5 0 1.41-.91 2.72-2 3.25V8.59c.58-.45 1-1.27 1-2.09C10 5.22 8.98 4 8 4H4c-.98 0-2 1.22-2 2.5S3 9 4 9zm9-3h-1v1h1c1 0 2 1.22 2 2.5S13.98 12 13 12H9c-.98 0-2-1.22-2-2.5 0-.83.42-1.64 1-2.09V6.25c-1.09.53-2 1.84-2 3.25C6 11.31 7.55 13 9 13h4c1.45 0 3-1.69 3-3.5S14.5 6 13 6z\"></path></svg></a>통과 코드:</h3>\n<div class=\"gatsby-highlight\" data-language=\"cpp\"><pre class=\"language-cpp\"><code class=\"language-cpp\"><span class=\"token macro property\"><span class=\"token directive-hash\">#</span><span class=\"token directive keyword\">include</span> <span class=\"token string\">&lt;iostream></span></span>\n\n<span class=\"token keyword\">using</span> <span class=\"token keyword\">namespace</span> std<span class=\"token punctuation\">;</span>\n\n<span class=\"token keyword\">int</span> <span class=\"token function\">main</span><span class=\"token punctuation\">(</span><span class=\"token punctuation\">)</span><span class=\"token punctuation\">{</span>\n    cin<span class=\"token punctuation\">.</span><span class=\"token function\">tie</span><span class=\"token punctuation\">(</span><span class=\"token constant\">NULL</span><span class=\"token punctuation\">)</span><span class=\"token punctuation\">;</span>\n    ios_base<span class=\"token operator\">::</span><span class=\"token function\">sync_with_stdio</span><span class=\"token punctuation\">(</span><span class=\"token boolean\">false</span><span class=\"token punctuation\">)</span><span class=\"token punctuation\">;</span>\n\n    <span class=\"token keyword\">int</span> t<span class=\"token punctuation\">,</span> a<span class=\"token punctuation\">,</span> b<span class=\"token punctuation\">;</span>\n    cin <span class=\"token operator\">>></span> t<span class=\"token punctuation\">;</span>\n\n    <span class=\"token keyword\">while</span><span class=\"token punctuation\">(</span>t<span class=\"token operator\">--</span><span class=\"token punctuation\">)</span><span class=\"token punctuation\">{</span>\n        cin <span class=\"token operator\">>></span> a <span class=\"token operator\">>></span> b<span class=\"token punctuation\">;</span>\n        cout <span class=\"token operator\">&lt;&lt;</span> a<span class=\"token operator\">+</span>b <span class=\"token operator\">&lt;&lt;</span> <span class=\"token string\">\"\\n\"</span><span class=\"token punctuation\">;</span>\n    <span class=\"token punctuation\">}</span>\n    <span class=\"token keyword\">return</span> <span class=\"token number\">0</span><span class=\"token punctuation\">;</span>\n\n<span class=\"token punctuation\">}</span></code></pre></div>","frontmatter":{"title":"[백준 알고리즘] 8958번: OX퀴즈","date":"May 05, 2020"}}},"pageContext":{"slug":"/Problem-Solving/2019-12-30-8958번-OX퀴즈/","previous":{"fields":{"slug":"/Problem-Solving/2019-12-31-1764번-듣보잡/"},"frontmatter":{"title":"[백준 알고리즘] 1764번: 듣보잡","category":"Problem-Solving","draft":false}},"next":{"fields":{"slug":"/Problem-Solving/2019-12-30-1712번-손익분기점/"},"frontmatter":{"title":"[백준 알고리즘] 1712번: 손익분기점","category":"Problem-Solving","draft":false}}}},"staticQueryHashes":["2486386679","3128451518"]}